However, such completeness is not always known. These two statements provide a complete description of the motion of an object. And if a second car is known to accelerate from a rest position with an eastward acceleration of 3.0 m/s 2 for a time of 8.0 seconds, providing a final velocity of 24 m/s, East and an eastward displacement of 96 meters, then the motion of this car is fully described. For example, if a car is known to move with a constant velocity of 22.0 m/s, North for 12.0 seconds for a northward displacement of 264 meters, then the motion of the car is fully described. Knowledge of each of these quantities provides descriptive information about an object’s motion. These equations are known as kinematic equations.There are a variety of quantities associated with the motion of objects – displacement (and distance), velocity (and speed), acceleration, and time. In Lesson 6, we will investigate the use of equations to describe and represent the motion of objects. The variety of representations that we have investigated includes verbal representations, pictorial representations, numerical representations, and graphical representations (position-time graphs and velocity-time graphs). If Crusty accelerated at 5 m/s2 and his initial velocity was 0 m/s, what was the velocity of Crusty when he hit the Jell-O? What we know Vi= 0 m/s a= 5 m/s2 D = 35 m = (0 m/s)2 + (35m) = 0 m2/s2+ 2 = 2 = 18.Kinematic Equations: The goal of this first unit of The Physics Classroom has been to investigate the variety of means by which the motion of objects can be described. If the cart has a beginning speed of 2.0 m/s, what is its final speed? What we know Vi= 2.0 m/s a= 4.0 m/s2 t= 5.0 s = (2.0 m/s) + (5.0 s) = 2.0 m/s + = 22 meters/seconds Term to find out Vf= Final Velocity The Formula we will useįinal Velocity Equation Vf2= Vi2+ 2ad Vf= Final Velocity Vi= Initial Velocity a= Acceleration d= displacement * Use this equation when you have no t*Ĭrusty the Clown gets shot 35 meters out of a cannon and into a vat of Jell-O. How far did the car move during this time? = (40 m/s)(5 seconds) + (5 seconds) = (200m) + (25 seconds = (200m) + (125 m) =325meters What we know a = 10 m/s2 Vi= 40 m/s t = 5 seconds Term to find out D = distance The Formula we will useįinal Velocity Equation Vf= Vi + at Vf= Final Velocity Vi= Initial Velocity a= Acceleration t= Time * Use this equation when you have no Vf*Ī cart rolling down an incline for 5.0 seconds has an acceleration of 4.0 m/s2. Frazier’s noggin’? = (10 m/s)2 – (5 m/s) 2 2(5m) = 100 m2/s2 – 25 m2/s2 10 m =75 m2/s2 10 m = 7.5 m/s2 What we know Vf= 10 m/s Vi= 5 m/s D = 5 meters Term to find out a = acceleration The Formula we will useĭisplacement Equation d= displacement Vi = initial velocity T = time A = acceleration * Use this equation when you have no Vf*Ī car traveling at 40 m/s accelerates at 10 m/s2 for 5 seconds. If the baguette started at 5 m/s and ended at 10 m/s, how fast did the baguette accelerate toward Ms. A visitor from Quebec, standing 5 meters away, overhears the joke and throws a baguette at Ms. Frazier makes a joke about French Canadians in the middle of Whole Foods. Quantities used in Kinematic Equations d = Displacement t = Time vf = Final velocity vi = Initial velocity (vo) a = AccelerationĪcceleration Equation a = v t a = Vf- Vi t Units are m/s2 (distance / time2)Īcceleration Equation a= acceleration Vf= Final Velocity Vi = Initial Velocity D= displacement ∆= Change in *Use this equation when you have no t* Kinematics Equations used to describe& representthe motion of objectsare known as kinematic equations.
0 Comments
Leave a Reply. |
AuthorWrite something about yourself. No need to be fancy, just an overview. ArchivesCategories |